Hello bright minds,
First off let me say that have a degree in computer engineering, which is essentially the same as an electrical engineering degree but with more programming courses (at least when I was in college in anyways 2000-2005). That said, I should probably turn in my engineering card because I have failed miserably!!
I thought I had a handle on this but clearly I don't.
So I have mostly built 48V 16S packs using LEV60 cells that have a capacity of 74Ah. Which works out to about 3.7KWh of juice. I know that number may come out differently when calculated but I'm going with what is stamped on the server rack style metal case designed for it, it says 3.7KWh so that's why I'm stating that number.
I bought a Kill-a-watt meter to measure how much power my office uses when I work from home and I left it plugged in few days to see what it would come out to. Between an active day of work (9hrs) plus the rest of the day/night with the monitors off. I noticed during "work" hours I was pulling 170-190 watts or perhaps I should say Voltamps thats what the Victron says in one of the screens and when I'm not working it would drop down to about 50 watts or so. (Monitors man!!) So this was obviously AC wattage. The Kill-a-watt hit 3.7KWh of use in about 2-3 days or so.
How do i properly calculate the wattage of my battery pack in DC watts? Then how do I calculate the amount of usage of energy of a an AC device over a period of an hour. I thought that if a device uses says 1000 watts of AC energy when in use then say 1 hour would be AC 1KWh of power consumed. Yes? No? Help?
Can someone explain how I can translate DC watts of my battery pack total to the amount of AC watts correctly?
Clearly watts are not just watts (DC vs AC) or there's some other factors in play I'm missing.
I figured since the Kill-a-watt meter didn't break 1KWh for along time that it would be no problem using my battery to run my office, instead a ended up with a dismal 4 hours approx runtime before I ran out of juice ( assuming its not plugged into the incoming solar energy ).
How do I properly do these conversions, looking for the equations and explanation not a link to a website that does it all for you.
Thanks!
For example I wanted to power my fridge during the day when I have plenty of excess power from the panels, the fridge uses 900 watts. I have no idea how to properly calculate say 8 hours of usage and translate that into how many DC watts my pack needs to be.
Not sure how much any of this extra info helps but here's the setup I'm using:
400watt panels 6x of them
Victron 250/60 SCC
Victron 48/800 Inverter
16S 74AH Batteries, brand new. Charged to 3.55 (full) and shutoff at 3V. Current config settings on the BMS. (JBD BMS)
No sure if I have my solar power input connected, then mostly my batter is just sitting there at float and the panels are powering everything.
I was thinking of building a 16S pack using these EVE batteries that seem to be what most people use, I was looking at the 314AH ones. But this gets expensive and I don't know how long I could power say my office or my fridge, if its just a few hrs then jeez how big are the ESS banks people are building to power way more things for way longer times??! I've never seen one of these EVE or CALB batteries (whatever bateryhookup or jag35 carries they are my main sites for batteries, got a better place please tell me!!) in the flesh so I don't know how big they are. Yes I've read the specs of them but that doesn't compare to holding one.I have a feeling they are huge.
Long post I know, but please help
First off let me say that have a degree in computer engineering, which is essentially the same as an electrical engineering degree but with more programming courses (at least when I was in college in anyways 2000-2005). That said, I should probably turn in my engineering card because I have failed miserably!!
I thought I had a handle on this but clearly I don't.
So I have mostly built 48V 16S packs using LEV60 cells that have a capacity of 74Ah. Which works out to about 3.7KWh of juice. I know that number may come out differently when calculated but I'm going with what is stamped on the server rack style metal case designed for it, it says 3.7KWh so that's why I'm stating that number.
I bought a Kill-a-watt meter to measure how much power my office uses when I work from home and I left it plugged in few days to see what it would come out to. Between an active day of work (9hrs) plus the rest of the day/night with the monitors off. I noticed during "work" hours I was pulling 170-190 watts or perhaps I should say Voltamps thats what the Victron says in one of the screens and when I'm not working it would drop down to about 50 watts or so. (Monitors man!!) So this was obviously AC wattage. The Kill-a-watt hit 3.7KWh of use in about 2-3 days or so.
- So I assumed my DC battery at 3.7KHw hrs could handle the job for 2 days before needing a recharge. HA!!! Boy was I so wrong....
- I was led to believe that the unit of measure 'watts' was not impacted by AC or DC, meaning if something reads 100 watts AC it was the same as 100 watts DC. Sounds like not the case.
- My battery fully charged (3.5-6V) lasted slightly over 4 hours before it was out of juice (3.0V). Looking at the inverter it said it was pulling 170-190 VA. I've always been confused by this Volt Amps unit of measure.
- So I need a math lesson.
How do i properly calculate the wattage of my battery pack in DC watts? Then how do I calculate the amount of usage of energy of a an AC device over a period of an hour. I thought that if a device uses says 1000 watts of AC energy when in use then say 1 hour would be AC 1KWh of power consumed. Yes? No? Help?
Can someone explain how I can translate DC watts of my battery pack total to the amount of AC watts correctly?
Clearly watts are not just watts (DC vs AC) or there's some other factors in play I'm missing.
I figured since the Kill-a-watt meter didn't break 1KWh for along time that it would be no problem using my battery to run my office, instead a ended up with a dismal 4 hours approx runtime before I ran out of juice ( assuming its not plugged into the incoming solar energy ).
How do I properly do these conversions, looking for the equations and explanation not a link to a website that does it all for you.
Thanks!
For example I wanted to power my fridge during the day when I have plenty of excess power from the panels, the fridge uses 900 watts. I have no idea how to properly calculate say 8 hours of usage and translate that into how many DC watts my pack needs to be.
Not sure how much any of this extra info helps but here's the setup I'm using:
400watt panels 6x of them
Victron 250/60 SCC
Victron 48/800 Inverter
16S 74AH Batteries, brand new. Charged to 3.55 (full) and shutoff at 3V. Current config settings on the BMS. (JBD BMS)
No sure if I have my solar power input connected, then mostly my batter is just sitting there at float and the panels are powering everything.
I was thinking of building a 16S pack using these EVE batteries that seem to be what most people use, I was looking at the 314AH ones. But this gets expensive and I don't know how long I could power say my office or my fridge, if its just a few hrs then jeez how big are the ESS banks people are building to power way more things for way longer times??! I've never seen one of these EVE or CALB batteries (whatever bateryhookup or jag35 carries they are my main sites for batteries, got a better place please tell me!!) in the flesh so I don't know how big they are. Yes I've read the specs of them but that doesn't compare to holding one.I have a feeling they are huge.
Long post I know, but please help
