there are 3 panels the SCC for each is 9.17 so ok on the panels. In series it would be 8.5 In parallel additive to 25.5 .
I have a marine solar install: 900 w from 3 solar panels with a Victron smart charger controller. I need 160-200 Ah to run the vessel 24 hrs. 24 v boat.
24V system times 200Ah is 4800Wh per day plus overhead of an inverter and efficiency losses
With 900W of solar, you need a yield over 6 hours long of high yield just to cover daily needs charging a LFP battery. The best money spent is on efficiency and energy conservation, I'd seriously look at what you can do to implement reduced load and energy consumption. Peak output is at high midday sun, on each side of midday sun, the yield is less.
Series connection on the panels gives me lots of V but low amps. (135 V /8.5 A continuous in ideal sun). Parallel connection on the panels gives me high amps (45 V /24 A).
Must be some difference in you calculations because the watts don't agree in both scenarios. The 135V/8.5A comes to 1,147.5W and 45V/24A= 1080W
Doesn't matter though. Unless you have shading problems, which is highly unlikely on a boat, the panels in series will always yield more watts due to the higher voltage (less voltage drop) and less power loss. Power loss is current squared times resistance.
I am confused on this one point as everyone says hook the solar panels up in series for more V but the controller would limit the V to the batteries to say, 30 V max. Right? So why the excess in V? In parallel, I would get around 40-45 V and 24 A.
So, how do I get the amps needed?
Don't worry about amps, you use watts.
I know about sun hrs /day cable needs, etc. but can't reconcile this one point.
Does the Victron see only Watts and with battery feedback, make magic adjustments to feed the batteries high amps if in series?
The SCC will just convert high voltage PV current to the system voltage.
Take the 135V/8.5A peak output and a 24V system. The SCC will reduce the voltage to what is needed to charge the battery. In your case, it appears to be lead acid (more on this later) which would be around 29.2V max. The 1148 watts produced at peak output would be converted to 29.2V at 39.30A.
Here is the next problem with your system and that is the lead acid batteries. Lead acid chemistry requires an absorption charge to reach full charge. You need to keep lead acid chemistry close to a full charge on a daily basis if possible to prevent sulfation and reduced capacity. The problem with absorption is it takes time because the internal resistance of the battery will be higher as it nears full charge and the amperage will be reduced. You did not state what Ah size the 6V batteries are but I'll assume 200Ah and you have 2 banks(4 x 6V each), which you want to parallel together. That gives a total size of 400Ah with 2 banks in parallel. With lead acid, you have 50% useable capacity, so with 200Ah used per day, you would be OK with that size of bank in parallel. But it will take way more than the 6 hours I mentioned above due to the absorption charge. I doubt you will be able to reach full charge in a day. It won't matter if you add more panels, once you hit absorption, the battery will only accept X number of watts.
Again, I can't stress it enough, look seriously at load reduction and energy conservation. More efficient appliances, changing lighting to led and adding timers, more efficient food storage (refrigerator and/or freezer). You would also benefit from a switch to LFP batteries, LFP gives increased useable capacity and no absorption charge plus you can partially charge and not worry about sulfation.