Hi there, I have a 500W inverter I am planning to power with 280aH array of 4 cells and a 100A BMS.
Doing the basic calculation as follows 500W inverter max load/12V battery = 41 Amps. I need a wire thick enough to carry 41A
Based on Will's advice in his book, I based my max load on the inverter and ordered 10AWG wire to connect the BMS and battery to the inverter:
"500 watt inverter requires 10 gauge"
and further for the fuse, I purchased a 50A:
"500 watt inverter should have a 50 amp fuse"
here is wills chart
Going off of this, my wire will burn out before my fuse?
This one has its max current at 30A
Doing the basic calculation as follows 500W inverter max load/12V battery = 41 Amps. I need a wire thick enough to carry 41A
Based on Will's advice in his book, I based my max load on the inverter and ordered 10AWG wire to connect the BMS and battery to the inverter:
"500 watt inverter requires 10 gauge"
and further for the fuse, I purchased a 50A:
"500 watt inverter should have a 50 amp fuse"
here is wills chart
- However, doing an image search I have found charts that do not clearly indicate that 10AWG can carry this current.
- Google search indicates max current of 10AWG is 40A - Some results indicate only 30A
- https://www.engineeringtoolbox.com/wire-gauges-d_419.html (3 cores can only carry 30A, single core can carry 52A)
Going off of this, my wire will burn out before my fuse?
This one has its max current at 30A