Hi all. I’m new to the forum. I have a 200 watt portable system I built a few years ago to support my very modest power needs when dry camping/boondocking in my camper.
200 watts is way overkill for my needs and has worked very well for several seasons (we only camp from June – September). All interior lights are converted to LED. Only one or two lights are ever operated at one time. And for no more than for 30 minutes a day, right before bed. The rest of the camper has a constant 9 watt draw which runs the electronics for the gas fridge and a gas leak detector.
This past season I added a 12 volt fridge/cooler that uses 36 watts when the compressor cycles on. How frequently and for how long it cycles is of course dependent on ambient temperature, how often it is opened to access the contents, etc.. So its total watt/hours consumed in a day is variable, but needless to say it has significantly increased my power demand. My solar system still keeps up, but it's closer than I'd prefer.
My question is about extracting the most power from my panels during the day.
I have unobstructed sun exposure from about 7:45 am through 3 pm.
At midday, with unobstructed sun, my panels are capable of putting out about 9 amps max. (measured at the input terminals of the charge controller) By 11:00 am each day, the Bulk stage on my battery bank (two 6 volt golf car batteries) is complete and the controller has transitioned to the Absorption stage so is putting just 2-3 amps to the batteries. So each day there’s about 4 hours (11:00 am – 3 pm) where 6-7 amps of potential generation is not being realized because the batteries don’t need it. But my 12 volt fridge/cooler is still consuming power.
If I ran the fridge/cooler from the Load terminals rather than from the battery, would the charge controller recognize this and draw more current from the panels when the fridge/cooler cycles on?
Thanks in advance for any insight.
200 watts is way overkill for my needs and has worked very well for several seasons (we only camp from June – September). All interior lights are converted to LED. Only one or two lights are ever operated at one time. And for no more than for 30 minutes a day, right before bed. The rest of the camper has a constant 9 watt draw which runs the electronics for the gas fridge and a gas leak detector.
This past season I added a 12 volt fridge/cooler that uses 36 watts when the compressor cycles on. How frequently and for how long it cycles is of course dependent on ambient temperature, how often it is opened to access the contents, etc.. So its total watt/hours consumed in a day is variable, but needless to say it has significantly increased my power demand. My solar system still keeps up, but it's closer than I'd prefer.
My question is about extracting the most power from my panels during the day.
I have unobstructed sun exposure from about 7:45 am through 3 pm.
At midday, with unobstructed sun, my panels are capable of putting out about 9 amps max. (measured at the input terminals of the charge controller) By 11:00 am each day, the Bulk stage on my battery bank (two 6 volt golf car batteries) is complete and the controller has transitioned to the Absorption stage so is putting just 2-3 amps to the batteries. So each day there’s about 4 hours (11:00 am – 3 pm) where 6-7 amps of potential generation is not being realized because the batteries don’t need it. But my 12 volt fridge/cooler is still consuming power.
If I ran the fridge/cooler from the Load terminals rather than from the battery, would the charge controller recognize this and draw more current from the panels when the fridge/cooler cycles on?
Thanks in advance for any insight.