26awg, 58v, 1 ft = voltage drop of .0051
26awg, 58v, .5 ft = voltage drop of .0025
My BMS claims to have read accuracy of .001 I believe, and my battery
has each cell, typically within .001 to .01 volts of each other, typically
.003
This would result in a difference of 2.6mV but significantly...