Just checked the battery voltage. The 8 batteries in the back are 12.55v, the bank in front is a little weird. The battery on the left is 12.22, both middle ones are 12.98 and the right one is 12.39. Does that mean the outer ones are both bad and dragging the system down. Why would the ones in between them be so much higher?
You need to charge them all up, then apply an equalization to them.. When that's done, measure voltage.
Go to your local auto store and buy a $9 hydometer and check water.
It is entirely possible for a lead acid battery to show good voltage but still be bad. Frequently, but not always, they need to be charged all the way up, then put under load to test.
Every battery in each string should be within around 0.1 volts of each other.. 12.22 sounds low if you have some at 12.98.. that's a significant difference.
It is the equalization charge that brings up all cells to the same voltage. An equalization charge will overcharge some cells that don't need a charge, but it will not charge them with enough juice do damage the cells.. but as the equalization charge is applied, those cells lagging behind will come up in voltage to meet the higher ones.
So to start a diagnosis, you need to start with a fully charged system.. and if your voltage variance is that wide, you should apply an equalization charge. Equalization charges should be applied regularly.. frequency varies, but generally its every three to four weeks or so. It kind of depends on the characteristics of how the batteries are cycled.. How deep, how often, etc.
Those batteries you have will die fast if you drop them below 70% SOC.. True deep cycle flooded batteries can go to 50%, but even then its not healthy for them. The bats you have are a sort of bastardized starting battery.. Not a true start battery, not a true deep cycle.
On top of this SOC limitation, are some conditions.. The lower you drop, the faster you must get them charged back up to prevent excess damage. "Faster" refers to both speed of charge, and how much time you have before applying that charge.