Guys,
On the ANT BMS the left hand balance connector has 10 white wires and 2 red wires. The right hand one has 1 black and 13 white. This gives me a total of 23 white. I know that the black is the neg and the final red is supposedly power for BMS. I'm presuming the second to last red is the 24th balance lead and should be left unattached.
So in summary I am going to connect as follows
Black to negative
White leads 1 through 15 to the positives of each cell
White lead 16 and final red lead to positive end of bank
This will leave white leads 17 through 23 unattached and the first of the 2 red leads unattached
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