looking at your calc, and making progress on the T200-8 core you got 15V/us from a graph? I looked and can not find that.
To calc H you need a mean length?
I have a very old Micrometals catalogue "Iron powder cores for power conversion and line filter applications" here.
Could not find it on the internet, its a pretty old catalogue.
You could order a copy, I presume its free ?
http://www.iec-international.com/micrometals/micrometals/catalog.html
In that on page 23 is a table of "volt microseconds" with various sized -8 cores that produces a 15C temperature rise.
That is where the 15 volt microseconds came from. Its actually for a T184 at 50Khz -8 material.
Not all core sizes are listed, but T184 is the closest size in the list.
In the same book on page 8, all the core physical sizes and materials are listed in sequence smallest to largest.
Physical dimensions are shown, outside diameter, inside diameter, core height, and also the "L" value in one column, which is the effective magnetic path length around the toroid. Its sort of a mean path length.
T200 core is shown as L = 13.0cm magnetic path length.
I wound a T200-8 inductor a full single layer has 44turns which measures 80uh. 42.5nHx44x44=82uh.
Great that works and then 90% due DC bias. effective 74uH
First you need to work out H, the magneto motive force in Orsteads for the turns and dc current yo plan to run. That will dc bias the core.
0.4 Pi times amps, times turns, divided by magnetic path length in cm.
For 44 turns and twenty amps, its 0.4 x 3.142 x 44 turns x 20 amps, all divided by 13.0 cm = 85 Orsteads.
Then you look at the magnetisation curve for -8 material. It has Orsteads on the X axis and % permeability on the Y axis.
Draw a line up from 85 Orsteads until it intersects the -8 curve. It looks like about 85% of initial permeability.
Magnetisation curve is here, top right hand curve for -8 material.
https://www.micrometals.com/products/materials/-8/
Now if you just test your 44 turns without any dc, it should read as having 42.5nH x 44 x 44 = 82uH.
But with 20 amps of steady dc, you will be down to only 85% of that, perhaps about 70uH
For the second core, if I dont have the V/us, ??
This MS inductor has 40turns and measures 180uH
All this is complicated enough, but what makes it all far worse is there is no standardisation of how the information is presented, as well as the mix of imperial and metric units. Core loss versus temperature rise is particularly difficult, because its non liner with frequency, and the physical geometry (surface area) effects the cooling. So milliwatts per cubic something or other is not very helpful in estimating temperature rise. Unfortunately milliwatts per cm cubed versus frequency and flux density is now becoming the standard way of giving core loss figures.
I used volt microseconds per turn, given for a specific core size, shape, and and material, as a much more direct way to judge safe temperature rise, which my thirty year old catalogue fortunately provided. Easy, simple and convenient.
The more complicated way is to regard core loss in terms of the ac voltage across the winding and the frequency.
Faraday's (transformer) equation links ac voltage, turns, frequency, and core cross section in terms of flux swing in the core.
Then you use the loss curves which are straight lines drawn on log/log scales for a particular material to give a core loss figure in mW per cm cubed.
That tells you the core loss, but not the resulting temperature rise.
Its the top left hand curve:
https://www.micrometals.com/products/materials/-8/
Its a much more cumbersome and round about way, and it still does not tell you how hot the core is going to get.