This is easier .. But I want to ask about the preferred capacity 80%, which starts from .. 100% - 20%? Or from 80% - 0%, or from 90% -10%, or even from 95% - 15% ??Alternatively you can try 3.375 for your charge voltage and 3.0 for you low voltage disconnect.
See if that satisfies your use case.
If your preferred capacity is for cell longevity this would be my guess.or from 90% -10%
Charge the cells as high as you can without tripping the bms and then let them settle.If your preferred capacity is for cell longevity this would be my guess.
If your preferred capacity is to keep cells from going out of balance, then my answer would revolve around what voltages (high and low) they begin to significantly diverge.
Similarly, what voltage to you consider 100%? 0%?
The 100% voltage doesn't really matter after we have found the 90% voltage.Charge the cells as high as you can without tripping the bms and then let them settle.
That is 100%
When the first cell hits 2.5 volts that is 0%.
You mean that 80% starts from 90% - 10%? This means 3.54 - 2.62 volts .. Is this correct ??If your preferred capacity is for cell longevity this would be my guess.
If your preferred capacity is to keep cells from going out of balance, then my answer would revolve around what voltages (high and low) they begin to significantly diverge.
Similarly, what voltage to you consider 100%? 0%?
80% of starts at 90% and goes to 10%.You mean that 80% starts from 90% - 10%? This means 3.54 - 2.62 volts .. Is this correct ??
Where do your cells settle in an hour? That is when the surface charge (nearly 0 capacity) bleeds off. That is what I consider 100%; my cells settle to 3.35v fairly quickly.This means 3.54
You want to program your BMS HVD and LVD at 3.65 volts and 2.50 volts respectively. The BMS is to be used for the last line of defense in case there is a malfunction with another device in the system...like your inverter. I am attaching a file that may help you. Keep in mind there can be slight variations because every cell is slightly different. But this is in the right ball park.Hi .. I have EVE batteries 280Ah 8 cells 24V .. I want to use 80% so that they last long .. What is the highest voltage and lowest voltage for charging and discharging that I will program the BMS and inverter with to give 80%?
I suspect you mean 13.8 which is 3.45 v per cell. That works for them in the context of using 14.6 volts for charge setting. That is 3.65 volts per cell and I think they warranty their batteries. I have no warranty on my EVE cells so I only charge to 3.4 volts per cell and float for a few hours from solar at 3.35 volts. This thread is full of seven pages of opinions on the subject.Lithium Werks recommends a float voltage of 3.8V for its U1-12RT
Yes, 13.8V, as the Valence document that I appended says. I've corrected my post, where I missed the "1" and said 3.8V.I suspect you mean 13.8
Where do your cells settle in an hour? That is when the surface charge (nearly 0 capacity) bleeds off. That is what I consider 100%; my cells settle to 3.35v fairly quickly.
2.62v seems like an aggressively low number for 10% SoC. where did you get that number?
Where did you get those numbers?I am charging at C 0.14 = 40 Ah , while the discharged at C 0.25 = 70Ah .
This is my daily use .. The charging speed was determined by the solar inverter.Where did you get those numbers?
Do you have a shunt or bms with similar function to map amp hours to voltage?
Those numbers just look way off compared to any charge or discharge curve I have seen.
With such a huge change (70-30%) over just a 0.2V range you're really not getting a very good idea of the actual SOC by using voltage. IMHO using a shunt/hall sensor is really the best way to tell how much power is left in your pack.
Yes. Good night.If I was to put my LiFePO4 at 13.10 volts, would I not be "close enough" to storage state (40%) to sleep comfortably?
If you can measure your battery voltage, you can live by this chart unless you're living on the edge of squeezing every amp hour out of your battery. I live between 13.0 ("getting low") and 13.3 ("looks pretty full").I mean, would I really need to dilly with a shunt, hall sensor and all that?
CMMWith such a huge change (70-30%) over just a 0.2V range you're really not getting a very good idea of the actual SOC by using voltage. IMHO using a shunt/hall sensor is really the best way to tell how much power is left in your pack.
Ghostwritter66I think JASONHC is correct ...
Charging LiFePO4 is a two step process … FIRST step uses constant current (CC) to reach about 60% State of Charge (SOC); And then STEP 2 kicks in until the charge voltage reaches 3.65V per cell. Turning from constant current (CC) to constant voltage (CV) means that the charge current is limited by what the battery will accept at that voltage, so the charging current tapers down asymptotically.
If you had to time the process – STEP ONE (60% SOC) needs about one hour and the STEP 2 (40% SOC) needs another two hours .. I have seen it that way ever since I started working with LiFePO4
MisterSandalsIf you can measure your battery voltage, you can live by this chart unless you're living on the edge of squeezing every amp hour out of your battery. I live between 13.0 ("getting low") and 13.3 ("looks pretty full").
Don't overthink it.
The big word you used doesn't work like you think it does. The Couloumbic efficiency of a LiFePo is indeed 99%. . . . at a moderate charge and cool ambient temperatures. Unfortunately, full batteries like to heat up, dropping that efficiency. While I agree the 3x the time claimed for the final 20% charge does seem a lot for a LiFePo since it isnt bothered by the stadium effect as much, it is not immune to it.That makes no sense. Couloumbic charge efficiency of LiFePO is about 100%. If you are charging with a constant current from 0% to 100% the last 20% (from 80% to 100%) takes exactly 20% of the time.
If you are trying to define your point of 80% charge from your table of voltages above, you are just fooling yourself. If you are not in the top or bottom "knees" of the curve, you need to have the cell resting for many hours before you can get any idea of charge state from voltage. Even then, it's extremely blunt.